(A) The general formula for solving a quadratic equation of the form $ax^2 + bx + c = 0$ is given by $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$. This fo

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(A) The general formula for solving a quadratic equation of the form $ax^2 + bx + c = 0$ is given by $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$. This formula is widely known as the quadratic formula or the Shridhar Acharya formula,named after the Indian mathematician Shridhar Acharya who derived it.

Class 10 Mathematics Quadratic Equations Mix Examples - Quadratic Equations

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Who gave the general formula to solve quadratic equations?

A
Shridhar Acharya
B
Aryabhatta
C
Pythagoras
D
Bhaskaracharya

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Mix Examples - Quadratic Equations

For a quadratic equation,if $\ldots \ldots \ldots \ldots$ then both the roots of an equation are distinct and real.

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Solve the following equation using the method of factorization and write its solution set: $\frac{9}{x-1} - \frac{2}{x-3} = \frac{5}{x+1}$

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Solve the following equation using the method of factorization: $\frac{x^{2}-1}{x^{2}+1}=\frac{7}{9}$

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If the roots of the following quadratic equation exist,find them by the method of completing the square: $x + \frac{2}{x} - 8 = 0$.

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The golden number $\frac{1+\sqrt{5}}{2}$ is one of the solutions of ...... .

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Who gave the general formula to solve quadratic equations?

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For a quadratic equation,if $\ldots \ldots \ldots \ldots$ then both the roots of an equation are distinct and real.

Solve the following equation using the method of factorization and write its solution set: $\frac{9}{x-1} - \frac{2}{x-3} = \frac{5}{x+1}$

Solve the following equation using the method of factorization: $\frac{x^{2}-1}{x^{2}+1}=\frac{7}{9}$

If the roots of the following quadratic equation exist,find them by the method of completing the square: $x + \frac{2}{x} - 8 = 0$.

The golden number $\frac{1+\sqrt{5}}{2}$ is one of the solutions of ...... .

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